Correct Answer - A::B::C::D
Given `|2z+3i| = |z^(2)|`
` because |2z+3i|le2|z|+3`
`implies |z|^(2)le2|z|+3`
`implies 0 le|z|le 3 " "...(1)`
Again `|2z+3i|ge|2|z|-3|`
`implies |z|^(2)ge|2|z|-3|`
`therefore |z|ge1" " …..(2)`
So,(1)`nn`(2)gives
`1le|z|le3`
Also,`|z|_("maximum")impliesz=3i`
So, `alpha=0,beta=3`
`&|z|("maximum") impliesz=-i`
So,`x=0, y=-1`