Question

Density of `2.05 M` solution of acetic acid in water is `1.02g//mL`. The molality of same solution is:
A. `3.28` mol `kg^(-1)`
B. `2.28` mol `kg^(-1)~
C. `0.44` mol `kg^(-1)`
D. `1.14` mol `kg^(-1)`

Answer 1

Correct Answer - B
Molality, `m=(M)/(1000d-MM_(2))xx1000`
where `M=` molarity, `d=` density, `M_(2)=` molecular mass
`m=(2.05)/(1000xx1.02-2.05xx60)=2.28 "mol" kg^(-1)`