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वक्र `x^(2//3)+y^(2//3)=2` के बिन्दु (1, 1) पर स्पर्शी व अभिलम्ब के समीकरण ज्ञात कीजिये |

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Correct Answer - `y+x-2=0, y-x=0`
`x^(2//3)+y^(2//3)=2" "implies" "(dy)/(dx)=-(y^(1//3))/(x^(1//3))`
बिन्दु (1, 1) पर स्पर्श रेखा की ढाल = -1
तथा अभिलम्ब की ढाल = 1
`:.` स्पर्श रेखा का समीकरण `y+x-2=0` है |
तथा अभिलम्ब का समीकरण `y-1=1(x-1)`
`implies" "y-x=0`

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