A dielectric slab fills the space between the plates of a parallel-plate capacitor. The magnitude of the bound charge on the slab is `75% of the magnitude of the free charge on the plates. The capacitance is `480muf` and the maximum charge that can be stored on the capacitor is `240varepsilon_(0)L^(2) E_(max)` where `E_(max)` is the breakdown field.
A. the dielectric constant for the dielectric slab is 4
B. without the dielectric, the capacitance of the capacitor would be `360muF`
C. the plate area is `60L^(2)`
D. If the dielectric slab is having the same area as the capacitor plate but the width half that of the capacitor, the capacitance would be `192muF`
