Question

Following is the graph between `log T_(50)` and `log a` (`a =` initial concentration) for a given reaction at `27^(@)C`. Hence order is

A. 1
B. 2
C. 3
D. 0

Answer 1

Correct Answer - D
`t_(1//2)prop((1)/(a))^(n-1)" or "t_(1//2)=k(a)^(1-n)`
`logt_(1//2)=logk+(1-n)loga`
(It represents straight line equation, y = c + mx)
Slope `=(1-n)=tan45^(@)=1`
`(1-n)=1implies n=0`