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If force `F`, Length `L` and time `T` are chosen as fundamental quantites, the dimensional formula for Mass is
A. `FL^(-1)T^(-2)`
B. `FL^(-1)T^(2)`
C. `FLT^(-2)`
D. `F`

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Best answer
Let `M=KF^(a)L^(b)T^(c )`
`= [MLT^(-2)]^(a)[L^(b)]T^(c )`
`=[M^(a)L^((a+b))T^((-2a+c))]`
`a=1`, `a+b=0` and `-2a+c=0`
`rArr a=1`, `b=-1`, `c=2`

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