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in Chemistry by (60.3k points)
Uranium (`""_(92)U""^(238)`) decayed to `""_(82)Pb""^(206)`. The process is `""_(92)U""^(238)underset(xalpha,ybeta)to.""_(82)Pb""^(206)`
`t""_(1//2)of U""^(238)=4.5xx10""^(9)` years
x and y in above decay series are
A. 6.8
B. 9.6
C. 8.8
D. 8.6

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1 Answer

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by (66.4k points)
Correct Answer - d
`alpha=(Ap-Ad)/4,beta=2xxalpha-(Zp-Zd)`

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