Correct Answer - C
`(2)/(3)Al_(2)O_(3)rarr(4)/(3)Al+O_(2),Delta_(r)G=+966"kJ"`
`therefore(2)/(3)(3O^(2-)),2O^(2-)rarrO_(2),thereforen=4`
`becauseDeltaG=-nFE`
`thereforeE=-(-DeltaG)/(nF)=-(9.66xx10^(3))/(4xx96500)=-2.5V`
`therefore` The potential difference needed for the reduction `=2.5V`