Question

Compound (A) has a neutralization equivalent of 116. It forms a semicarbazone or phenyl hydrazone, and gives positive iodoform test. Compound (A) gives n-pentane. What are (A), (B) and (C)?

Answer 1

(i) Since (A) forms semicarbazone and phenyl hydrazone, hence it has a gt C=O group.
As it also gives iodoform test hence it contains `H_(3)C-overset(O)overset(||)(C)-` group in its molecule.
(ii) The neutralization equivalent of (A) is 116, it is also contain a -COOH group. its formula can be deduced as followes
`116-H_(3)C-overset(O)overset(||)(C)-+-COOH=116-(43+45)=28`
The value 28 corresponding to two methyl groups.