Question

On treatment of 10 ml of 1M solution of the complex `CrCl_(3).6H_(2)O` with excess of `AgNO_(3)`, 4.305 g of AgCl was obtained. The complex is
A. `[CrCl_(3)(H_(2)O)_(3)].3H_(2)O`
B. `[CrCl_(2)(H_(2)O)_(4)]Cl.2H_(2)O`
C. `[CrCl(H_(2)O)_(5)]Cl_(2).H_(2)O`
D. `[Cr(H_(2)O)_(6)]Cl_(3)`

Answer 1

Correct Answer - D
no. moles of `Cl^(-)` = no. of moles of AgCl
`:.` The possible complex is `[Cr(H_(2)O)_(6)]Cl_(3)`