Correct Answer - C
`S_(N)1` reaction proceeds through formation of carbocation. Hence, more stable carbocation more reactivity towards `S_(N)1` mechanism.
Hence, the reaction will proceed thorugh `S_(N)1` mechanism when, `C_(6)H_(5)CH_(2)Br` is the substrate, because on ionisation it gives a resonance stabilised carbocation `(C_(6)H_(5)CH_(2))`