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+1 vote
41.8k views
in Physics by (130k points)
edited by

A 100 μF capacitor in series with a 40 Ω resistance is connected to a 110 V, 60 Hz supply. 

(a) What is the maximum current in the circuit? 

(b) What is the time lag between the current maximum and the voltage maximum?

1 Answer

+2 votes
by (93.7k points)
edited by
 
Best answer

Capacitance of the capacitor, C = 100 μF = 100 × 10−6

Resistance of the resistor, R = 40 Ω 

Supply voltage, V = 110 V 

(a) Frequency of oscillations, ν= 60 Hz

(b) In a capacitor circuit, the voltage lags behind the current by a phase angle of Φ. This angle is given by the relation:

Hence, the time lag between maximum current and maximum voltage is 1.55 ms.

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