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यदि `2^(x)=3^(y)=6^(-z)` है तो `(1/x+1/y+1/z)` किसके बराबर हैं ?

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`2^(x)=3^(y)=6^(-z)=k`
`implies2=k^(1//x),3=k^(1//y)=6=k^(-1//z)`
`:.2xx3=6`
`k^(1//x)xxk^(1//y)=k^(-1//z)`
`1/x+1/y=-1/zimplies1/x+1/y+1/z=0`

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