Correct Answer - C
The rate at which an object radiates energy is given as,
`Q/t sigma AT^(4) rArr` Power, `P = sigmaAT^(4)`
`:. A prop 1/(T^(4))`
It the body radiates same power, then
`rArr (A_(2))/(A_(1)) = (T_(1)^(2))/(T_(2)^(4)) rArr (4pir_(2)^(2))/(4pir_(1)^(2)) = (T_(1)^(4))/(T_(2)^(4))`
`:. (r_(2))/(r_(1)) = ((T_(1))/(T_(2)))^(2)`