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The angle between the lines `2x=3y=-z and 6x=-y=-4z` is (A) `0^0` (B) `90^0` (C) `45^0` (D) `30^0`
A. `30^(@)`
B. `45^(@)`
C. `90^(@)`
D. `0^(@)`

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Correct Answer - C
The given lines can be rewritten as `x/3=y/2=z/(-6) and x/2 =(y)/(-12)=z/(-3)`
Angle between the lines is
`theta=cos^(-1)((3xx2(-12)-(-3)(-6))/(sqrt(3^(2)+2^(2)+(-6)^(2))sqrt((2)^(2)+(-12)^(2)+(-3)^(2))))=0`
`theta=90^(@)`

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