Correct Answer - C
Let the position vectors of the points A,B,C are `vec0, veca+vecb,veca-vecb and theta =90^(@)`
`:.` Area of triangle `=(1)/(2)|vec(AB)xx vec(AC)|`
`=(1)/(2)| (veca+vecb)xx(veca -vecb)|`
`=(1)/(2)| 2 vecb xx veca|`
`=|vecb||veca|sin theta`
`=3xx2 sin 90^(@)`
`=6`