Question

In a resonance pipe the first and second resonance are obtained at depths 22.7 cm and 70.2 respectively. What will be the end correction?
A. 1.05 cm
B. 115.5 cm
C. 92.5 cm
D. 113.5 cm

Answer 1

Correct Answer - A
For end correction x ,
`(l_(2)+x)/(l_(1)+x)=( 3lambda//4)/(lambda//4)=3 `
` implies x=(l_(2)-3l_(1))/(2)`
`=(70.2-3 xx 22.7)/(2)=1.05 cm`