Correct Answer - A
Given equation of line is ` x^(2)-4xy+3y^(2)=0`
`:. m_(1)+m_(2)=(4)/(3) and m_(1)m_(2)=(1)/(3)` .
On solving these equations , we get `m_(1)=1,m_(2)=(1)/(3)`
Let the line parallel to given line are `y=m_(1)x+c_(1) and y=m_(2)x+c_(2) `
`:. y=(1)/(3) x+ c_(1) and y=x+c_(2)`
Also, these lines passes through the point (3,-2)
`:. -2=(1)/(3)xx 3 +c_(1)`
`implies c_(1)=-3 `
and `-2=1 xx 3 +c_(2)`
`implies c_(2)=-5 `
`:.` Required equation of pair lines is
(3y-x+9)(y-x+5)=0
`implies x^(2)+3y^(2)-4xy-14x+24y+45=0`
