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The pressure of a gas is 100 k Pa. if it is compressed from 1 `m^(3)` to `10 dm^(3)` , find the work done .
A. `990 J`
B. 9990 J
C. 9900 J
D. 99000 J

1 Answer

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Correct Answer - D
Given ,
pressure , `p = 100 k Pa = 10^(5)` Pa
Initial volume , `V_(1) = 1m^(3)`
Final volume , `V_(2) = 10 xx 10^(-3) m^(3) = 10^(-2) m^(3)`
W = `p Delta V`
`=10^(5) (1 - 10^(-2)) = 99,000 J`

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