Question

Two springs have their force constants `K_(1)` and `K_(2)` and they are stretched to the same extension. If `K_(2) gt K_(1)` work done is
A. more is spring A
B. more in speing B
C. equal in both
D. nothing can be said

Answer 1

Correct Answer - A
Work done is stretching (W) = stiffness of speing
`because K_(A) gt K_(B), W_(A)gt W_(B)`