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यदि (If) `y=log_(7)(log_(7)x)` (find) `(dy)/(dx)` ज्ञात करें।

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दिए है ,`y=log_(7)(logx)=(log(logx))/(log7)" " [log_(b)m=(logm)/(logb)]`
दिए हुआ फलन `xgt1` के लिए परिभषित है।
दोनों तरफ x के सापेक्ष अवकलित करने पर हमें मिलता है,
`(dy)/(dx)=(1)/(log7)(d)/(dx)(log(logx))`
`=(1)/(log7)(1)/(logx)*(d)/(dx)(logx)=(1)/(xlog7logx)`

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