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It a ≠ 0 and the line 2bx + 3cy + 4d =0 passes through the points of intersection of

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It a ≠  0 and the line 2bx + 3cy + 4d =0 passes through the points of intersection of the parabolas y2 = 4ax and xz = 4ay, then

(a) d2 + (2b + 3c)2 = 0

(b) d2 + (3b + 2c)2 = 0

(c) d2 + (2b - 3c)2 = 0

(d) d2 + (3b - 2c)2 = 0

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1 Answer

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Best answer

Correct Option (a) d2 + (2b + 3c)2 = 0

Explanation:

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If a ≠ 0 and the line 2bx + 3cy + 4d = 0.
asked Apr 16, 2018 in Mathematics by paayal (151k points)

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