Correct Answer - B
According to question,
`rArr (x+15^(@))+((6x)/5+6)^(@)+((2x)/3+30)^(@)`
`=180^(@)`
`angleA + angleB + angleC=180^(@)`
`rArr x+(6x)/5+(2x)/3=180^(@)-(15+6+30)`
`rArr 43x = 129 xx 15`
`x=45^(@)`
`rArr` Each angle
`rArr (x+15)^(2)= 45+15 = 60^(@)`
`rArr ((2x)/3+30)^(@)=60^(@)`
`therefore` All three angles are equal `60^(@)`
`therefore` Triangle will be equilateral triangle.
