Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
104 views
in Physics by (87.6k points)
closed by
A 44 mH inductor is connected to 220 V, 50 Hz a.c. supply. Determine rms value of current in the circuit.

1 Answer

0 votes
by (88.9k points)
selected by
 
Best answer
Inductance of inductor, `L=44mH=44xx10^(-3)H`
Supply voltage, V=220V
Frequency, v=50V
Angular frequenc, `omega=2piv`
Inductive reactivance, `x_(L)= 2pivL=2pixx50xx44xx10^(-3)Omega`
Rms value of current is given as:
`=(220)/(2pixx50xx44xx10^(-3))=15.92A`
Hence, the rms value of current in the circuit is 15.92A.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...