Correct Answer - B
`y=int x^(2)e^(x^(2)) dx x^(3) =t`
`x^(2) dx = 1/3 dt` ltbtgt `y=1/3 e^(x^(3)) +c`
passes through (0,1)
`1=1/3 +c rArr c= 2/3`
from (1), we have `y=1/3 e^(x^(3)) +2/3`
`rArr e^(x^(3)) =3y -2 rArr x^(3) =e n_(e)(3y-2)`
`rArr x = (en_(e)(3y -2))^(1//3)`