Correct Answer - C
As the compound is giving yellow precipitated with `NaOl` , this means it is undergoing haloform (iodoform) reaction. Haloform reaction is shown by the compounds having
`CH_(3)-underset(O)underset(||)(C)` or `CH_(3)-underset(OH)underset(|)(C)H-"group"`.
Hence the compound A is
`2NaOH + I_(2)rarr NaOl+Nal + H_(2)`
