Correct Answer - B
According to Hardy-Schuize law, greater the charge on anion greater will be its coagulating power.
`{:("Electrolytes","Anionic part","Charge on anion"),(Na_(2)S," "S^(2-)," "2),(Na_(3)PO_(4)," "PO_(4)^(3-)," "3),(Na_(2)SO_(4)," "SO_(4)^(2-)," "2),(NaCl," "Cl^(-)," "1):}`
Here,`PO_(4)^(3-)` have highest charge. Hence, `PO_(3)^(4)` have highest coagulating power.