Correct Answer - D
1 mole of `AgNO_(3)` precipitates one free chlorids ion `(Cl^(-))`.
Here, 3 moles of `AgCl` are precipitated by excess of `AgNO_(3)`. Hence, there must be three free `Cl^(-)` ions.
So, the formula of the complex can be `[Cr(H_(2)O)_(6)]Cl_(3)` and correct choice is (d).