The radius of a divaent cation `A^(2+)` is 94pm and of divalent anion `B^(2-)` is 146pm. The compound AB has:

Correct Answer - A
`(r_(A^(+2)))/(r_(B^(+2)))=(94)/(164)=0.64`
The radius ratio lies in between 0.414 to 0.732 so, cation should be in octahadral void therefore, structure will be Rock salt.

The radius of a divaent cation `A^(2+)` is 94pm and of divalent anion `B^(2-)` is 146pm. The compound AB has:

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