Question

Let `alpha,beta` be the roots of the equation `(x-a)(x-b)=c ,c!=0` Then the roots of the equation `(x-alpha)(x-beta)+c=0` are `a ,c` (b) `b ,c` `a ,b` (d) `a+c ,b+c`

Answer 1

Since `alpha, beta` are the roots fo
`(x-a)(x-b)=c`
or `(x-a)(x-b)-c=0`
Then `(x-a)(x-b)-c-(x-alpha)(x-beta)`
`implies(x-alpha)(x-beta)+c=(x-a)(x-b)`
Hence roots of `(x-alpha)(x-beta)+c=0` are a,b.