This inequation is equivalent to the collection of the systems
`[{(2x+3gt1),(x^(2)lt2x+3),(0lt2x+3lt1),(x^(2)gt2x+3):}implies[{(xgt-1),((x-3)(x+1)lt0):},{((-3/2ltxlt-1),((x-3)(x+1)gt0):}):}`
`implies[{(xgt-1),(-1ltxlt3):}, {(-3/2lt x lt-1),(xlt-1 "and" xgt3)implies-3/2ltxlt-1):}`
Hence the solution of the original inequation is
`x epsilon(-3/2,-1)uu(-1,3)`.
