Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
665 views
in Mathematics by (93.6k points)
closed by
Number of real roots of the equation `sqrt(x)+sqrt(x-sqrt((1-x)))=1` is

1 Answer

0 votes
by (92.3k points)
selected by
 
Best answer
Correct Answer - B
We have `sqrt(dx)+sqrt(x-sqrt((-x)))=1`
`impliessqrt(x-sqrt(1-x))=1-sqrt(x)`
On squaring both sides we get
`x-sqrt(1-x)=1+x-2sqrt(x)`
`implies-sqrt(1-x)=1-2sqrt(x)`
Again, squaring on both sides we get
`1-x=1+4x-4sqrt(x)`
`4sqrt(x)=5x`
`impliessqrt(x)=4/5` [on squaring both sides]
`impliesx=16/25`
Hence the number of real solutions is 1.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...