Correct Answer - D
Total number of triangles=Number of triangles with vertices on sides
`[(AB,BC,CD)+(AB,BC,DA)+(AB,CD,DA)+(BC,CD,DA)]`
`=.^(3)C_(1)xx.^(4)C_(1)xx.^(5)C_(1)+.^(3)C_(1)xx.^(4)C_(1)xx.^(6)C_(1)+.^(3)C_(1)xx.^(5)C_(1)xx.^(6)C_(1)+.^(4)C_(1)xx.^(5)C_(1)xx.^(6)C_(1)`
`=60+72+90+120=342`