Question

The gas liberated on heating a mixture of two salts with NaOH, give a reddish brown precipitate with an alkaline solution of K₂HgI₄. The aqueous solution of the mixture on treatment with BaCl₂ gives a white precipitate which is sparingly soluble in conc. HCl. On heating the mixture with K₂Cr₂O₇ and conc. H₂SO₄, red vapours are produced. The aqueous solution of mixture gives a deep blue colouration with potassium ferricyanide solution. Then, identify the radicals in the given mixture.

(a) NH₄⁺, Fe³⁺, SO₄^2-, NO₂^-

(b) CO₃^2-, Fe²⁺, SO₄^2-, Cl^-

(c) NH₄⁺, Fe²⁺, SO₄^2-, Cl^-

(d) NH₄⁺, Ca²⁺, SO₄^2-, Cl^-

Answer 1

Correct Option (c) NH₄⁺, Fe²⁺, SO₄^2-, Cl^-

Explanation:

(i) The mixture on heating with NaOH liberate a gas which gives red ppt. with alkaline K₂Hgl₄, so the gas is NH₃ and mixture contains NH₄⁺ ion.