आहीनियम समीकरण के अनसुार
`log k= log A – (E)/( 2.303RT)`
` k=2.481 xx 10^(-5) s^(-1) , E_(a) = 179990 j mol^(-1)`
` R = 8.314 j k^(-1) mol^(-1) , T= 546 k`
` log = A log k + .(E)/(2.303 RT)`
`= log (2.418 xx 10^(-5)) + ((179900 J mol^(-1)))/( 2.303 xx (8.314 Jk^(-1) mol^(-1)) xx 546 k)`
`=-4.6174 + 17.21 = 12. 5926`
`A = Antilog 12.5926 = 3.9 xx 10^(12) s^(-1)`