Question

Both the strings, shown in figure, are made of same material and have same cross-section. The pulleys are light. The wave speed of transverse wave in the string `AB` is `v_(1)` and in `CD` it is `v_(2)`, the `v_(1)//v_(2)` is

A. 1
B. 2
C. `sqrt2`
D. `(1)/(sqrt2)`

Answer 1

Correct Answer - D
`v=sqrt((T)/(u))`
[T = tension forse]
[`mu` = mass per unit length]