Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
2.2k views
in Physics by (90.7k points)
closed by
Two point charges of `1muC and -1muC` are separated by a distance of 100 Å. A point P is at a distance of 10 cm from the midpoint and on the perpendicular bisector of the line joining the two charges. The electric field at P will be
A. `9NC^(-1)`
B. `0.9NC^(-1)`
C. `90NC^(-1)`
D. `0.09NC^(-1)`

1 Answer

0 votes
by (91.3k points)
selected by
 
Best answer
Correct Answer - D
The point lies on equatorial line of a short dipole.
`therefore" "E=(2ql)/(4piepsilon_(0)r^(3))=(9xx10^(9)xx10^(-6)xx10^(-8))/((10^(-1))^(3))=0.09NC^(-1)`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...