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What is the molarity of a solution containing 10 g of NaOH in 500 mL of solution ?
A. `"0.25 mol L"^(-1)`
B. `"0.75 mol L"^(-1)`
C. `"0.5 mol L"^(-1)`
D. `"1.25 mol L"^(-1)`

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Correct Answer - C
No. of moles of NaOH=`10/40`=0.25 mol
`M=(0.25xx1000)/500=0.5 mol L^(-1)`

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