Question

Plot of log against log P is a straight line inclined at an angle of `45^(@)`. When the pressure is 0.5 atm and Freundlich parameter ,K is 10, the amount of solute adsorbed per gram of adsorbent will be : (log 5=0.6990 )
A. 5 g
B. 3 g
C. 6 g
D. 12 g

Answer 1

Correct Answer - A
According to Freundlich equation `((x)/(m)) =kp^(1//n) to log ((x)/(m)) = log k +(1)/(n) log p `
`therefore ` Plot of log x/m vs logp is linear with slope =1/n and intercept =log k.
Thus , `1/n= tan theta=tan 45^(@)=1 ` or n=1
At p =0.5 atm and k=10
`x/m = 10xx(0.5)^(1)=5" "therefore x=5 g`