Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
178 views
in Physics by (97.1k points)
closed by
Calculate the heat evolved for the rise of water when one end of the capillary tube of radius r is immeresed vartically into water. Asssume surface tension =T and density of water to be `rho`
A. `(2pi S)/(rho g)`
B. `(pi S^(2))/(rho g)`
C. `(2pi S^(2))/(rho g)`
D. `(4pi S^(2))/(rho g)`

1 Answer

0 votes
by (97.1k points)
selected by
 
Best answer
Correct Answer - C
Potential energy of water column,
`U = (mgh)/(2) = (2pi S^(2))/(rho g)`
The work performed by force of surface tension is
`W = 2pi rSh = (4pi S^(2))/(rho g)`
From conservation of energy the heat evolved,
`Q = W-U = (2pi S^(2))/(rho g)`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...