Correct Answer - B
Given that, two waves
`y=a sin (omega t-kx)` and `y=a cos (omega t-kx)`
Here, the phase difference between the two waves is `pi/2`.
So, the resultant amplitude, `A=sqrt(a_(1)^(2)+a_(2)^(2)+2a_(1)a_(2) cos phi)`
`["Here, "a_(1)=a, a_(2)=a and phi=pi/2]`
`:. A=sqrt(a^(2)+a^(2)+2a^(2)"cos"pi/2)`
or `A=sqrt(a^(2)+a^(2)+0)implies A=sqrt(2)a`