Correct Answer - a
The length of pipe closed at end of the first is
given by
`l_(1) (3l)/4` ...(i)
Length of the pipe open at both end for third ovretone is
given by `l_(2)=(4lambda)/2 = 2lambda` ... (ii)
Dividing Eqs. (i) by (ii), we get
`lambda_(1)/ lambda_(2) = (3lambda//4)/(lambda) = 3/8. `