Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
65 views
in Physics by (97.1k points)
closed by
A beam of light of wavelength 600 nm from a distant source falls on a single slit 1 mm wide and the resulting diffraction pattern is observed on a screen 2 m away. The distance between the first dark fringes on either side of the central bright fringe is
A. 1.2 cm
B. 1.2 mm
C. 2.0 cm
D. 2.0 mm

1 Answer

0 votes
by (97.2k points)
selected by
 
Best answer
Correct Answer - D
Fringe width, `beta=(lambdaD)/(d)=(500xx10^(-9)xx2)/(1xx10^(-3))=10xx10^(-4)m`
So, distance between the first dark fringes on eitherside of the central bright fringe
`X=2beta=2xx10xx10^(-4)m`
`=20xx10^(-4)m=2.0mm`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...