Question

Forr 14 g of CO, the wrong statement is
A. it occupies `2.24` L at NTP
B. It correspends to `1//2` mole of CO
C. It corresponds ot same mole of CO and nitrogen gas
D. it corresponds to `3.01xx 10 ^(23)` molecules of CO

Answer 1

Correct Answer - A
28 g of CO occuupies `= 22.4` L of CO at NTP
`therefore` 14 g of CO occupies `=22.4/28 xx 14 ` L of CO at NTP
`= 11, 2 ` L of CO at NTP
Thus, 14 g of CO occupies `11.2` L volume at NTP.
Thus, given statement is wrong.