Question

A certain substance decays to 1/232 of its initial activity in 25 days. Calculate its half-life.

Answer 1

Fraction of substance decays
`= ("Quantity remains")/("Initial quantity")`
`=(1)/(2^(n))=(1)/(32)=(1)/(2^(5))`
`therefore n = 5`
Duration of time = 2 days
We know `(n)=("Duration of time")/("Half life time")`
`therefore` Half life time `=("Duration of time")/(n)`
`(25)/(5)=5` days