Question

200 MeV energy is released when one nnucleus of `.^(235)U` undergoes fission. Find the number of fissions per second required for fissions per second required for producing a power of 1 megawatt.

Answer 1

E = 200 MeV
`P=1xx10^(6)W`
`P=(nE)/(t)rArr (n)/(t)=(P)/(E )= (10^(6))/(200xx10^(6)xx1.6xx10^(-19))`
`= (1)/(32)xx10^(18)`
`therefore P = 0.03125xx10^(18)`
`= 3.125xx10^(6)`