Question

If `x=111"...."(20 digits),y=333"...."(10digits) and z=222".....2"(10 digits), then (x-y^(2))/(z)` equals.
A. `(1)/(2)`
B. 1
C. 2
D. 4

Answer 1

Correct Answer - B
`:.x=(1)/(9)(999"...."9)=(1)/(9)(10^(20)-1)`
`y=(1)/(3)(999"...."9)=(1)/(3)(10^(10)-1)`
and `z=(2)/(9)(999"...."9)=(2)/(9)(10^(10)-1)`
`:.(x-y^(2))/(z)=((1)/(9)(10^(20)-1)-(1)/(9)(10^(10)-1)^(2))/((2)/(9)(10^(10)-1))`
`=(10^(10)+1-(10^(10)-1))/(2)=1`