60g of urea is dissolved in 1100g solution. To keep `DeltaT//K_(f)" as "1" mol"//kg`, water separated in the

Correct Answer - A
1100g" solution has 60 g urea. Thus",
`"water=1040g`
`DeltaT_(f)=(1000K_(f)w_(1))/(m_(1)w_(2))rArr(DeltaT_(f))/(K_(f))=(1000xx60)/(60xxw_(2))=1`
`:.w_(2)=1000g`
`"Thus, ice formed"=1040-1000=40g`

60g of urea is dissolved in 1100g solution. To keep `DeltaT//K_(f)" as "1" mol"//kg`, water separated in the form of ice is

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