Question

`2N_(2)O_(5)(g)to4NO_(2)+O_(2)(g)`
What is the ratio of the rate of decomposition of `N_(2)O_(5)`
to rate of formation of `NO_(2)`
A. `1:2`
B. `2:1`
C. `1:4`
D. `4:1`

Answer 1

Correct Answer - B
`2N_(2)O_(5) to 4 NO_(2) + O_(2)`
Rate of decomposition of `N_(2)O_(5) = - (1)/(2) (d[N_(2) O_(5)])/("dt")`
Rate of formation of `NO_(2) = (1)/(4) (d[NO_(2)])/("dt")`
`therefore ("Rate of decomposition of" N_(2)O_(5))/("Rate of formation of " NO_(2)) = (-(1)/(2) ""d([N_(2)O_(5)])/("dt"))/((1)/(4) ""d([NO_(2)])/("dt"))`
or `- (1)/(2) ""d ([N_(2)O_(5)])/("dt") xx (4)/(1) (dt)/(d[NO_(2)]) = - (4)/(2) = - (2)/(1) = - 2: 1`
Magnitude of the ratio of the rate of decomposition of `N_(2)O_(5)` to rate of formation of `NO_(2) = 2 : 1`