what is the energy \( ( kJ / mol ) \) associated with the de-excitation of an electron from \( n=6 \) to \( n= \) \( He ^{+} \)ion? \( 1.36 \times 10^{6} \) (b) \( 1.36 \times 10^{3} \) (c) \( 1.16 \times 10^{3} \) (d) \( 1.78 \times 10^{3} \)

Question

What is the energy (kJ/mol) associated with the de-excitation of an electron from n=6 to n=2 in He⁺ ion? 

a) 1.36×10⁶ b) 1.36×10³ c) 1.16×10³ d) 1.78×10³

Answer 1

Answer: c) 1.16 x10³  

n = 6 to n= 2

E = \(13.6\times Z_1^2[\frac{1}{4}-\frac{1}{36}]\)

\(=13.6\times 4\times[\frac{9-1}{36}]\)

\(=13.6\times4\times\frac{8}{36}\)

= 12.08 ev x 96kj/mol

=1.16 x 10³